58. Length of Last Word
easyString
read the problem on leetcode →
first solved 15 Aug 2024 · 2 accepted submissions
class Solution:
def lengthOfLastWord(self, s: str) -> int:
# lststr=s.split()
# return len(lststr[-1])
i = len(s) - 1
while i >= 0 and s[i] == " ":
i -= 1
length = 0
while i >= 0 and s[i] != " ":
length += 1
i -= 1
return length
class Solution:
def lengthOfLastWord(self, s: str) -> int:
words = s.strip().split()
if not words:
return 0
return len(words[-1])