88. Merge Sorted Array
easyArray · Two Pointers · Sorting
read the problem on leetcode →
first solved 31 Aug 2023 · 3 accepted submissions
class Solution:
def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None:
"""
Do not return anything, modify nums1 in-place instead.
"""
last = m+n-1
while m > 0 and n > 0:
if nums1[m-1] > nums2[n-1]:
nums1[last]=nums1[m-1]
m-=1
last-=1
else:
nums1[last]=nums2[n-1]
n-=1
last-=1
while n>0:
nums1[last]=nums2[n-1]
n-=1
last-=1class Solution:
def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None:
"""
Do not return anything, modify nums1 in-place instead.
"""
i=m-1
j=n-1
k=m+n-1
while j>=0:
if i>=0 and nums1[i]>nums2[j]:
nums1[k]=nums1[i]
k-=1
i-=1
else:
nums1[k]=nums2[j]
j-=1
k-=1
class Solution(object):
def merge(self, nums1, m, nums2, n):
"""
:type nums1: List[int]
:type m: int
:type nums2: List[int]
:type n: int
:rtype: None Do not return anything, modify nums1 in-place instead.
"""
nums1[:] = sorted(nums1[:m] + nums2[:n])