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125. Valid Palindrome

easy

Two Pointers · String

read the problem on leetcode →

first solved 14 Sept 2026

python
class Solution:
    def isPalindrome(self, s: str) -> bool:
        left = 0
        right = len(s) - 1

        while left < right:
            while left < right and not s[left].isalnum():
                left += 1

            while left < right and not s[right].isalnum():
                right -= 1

            if s[left].lower() != s[right].lower():
                return False

            left += 1
            right -= 1

        return True
Valid Palindrome · switch